1
KCET 2018
MCQ (Single Correct Answer)
+1
-0
Two cells of internal resistances $r_1$ and $r_2$ and of same emf are connected in series, across a resistor of resistance $R$. If the terminal potential difference across the cells of internal resistance $r_1$ is zero, then the value of $R$ is
A
$R=2\left(r_1+r_2\right)$
B
$R=r_2-r_1$
C
$R=r_1-r_2$
D
$R=2\left(r_1-r_2\right)$
2
KCET 2018
MCQ (Single Correct Answer)
+1
-0
The $I-V$ graphs for two different electrical appliances $P$ and $Q$ are shown in the diagram: If $R_P$ and $R_Q$ be the resistances of the devices, then KCET 2018 Physics - Current Electricity Question 5 English
A
$R_P=R_Q$
B
$R_P>R_Q$
C
$R_P
D
$R_P=\frac{R_Q}{2}$
3
KCET 2018
MCQ (Single Correct Answer)
+1
-0
The correct Biot-Savart law in vector form is
A
$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{l(d \mathbf{} \times \mathbf{r})}{r^2}$
B
$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{\mid(d \mathbf{} \mathbf{~} \times \mathbf{r})}{r^3}$
C
$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{|d|}{r^2}$
D
$d \mathbf{B}=\frac{\mu_0}{4 \pi} \cdot \frac{|d|}{r^3}$
4
KCET 2018
MCQ (Single Correct Answer)
+1
-0
An electron is moving in a circle of radius $r$ in a uniform magnetic field $B$. Suddenly, the field is reduced to $\frac{B}{2}$. The radius of the circular path now becomes
A
$\frac{r}{2}$
B
$2 r$
C
$\frac{r}{4}$
D
$4 r$
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