1
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

The sum of all the solution of the equation $$\cos \theta \cos \left( {{\pi \over 3} + \theta } \right)\cos \left( {{\pi \over 3} - \theta } \right) = {1 \over 4},\theta \in [0,6\pi ]$$

A
15$$\pi$$
B
30$$\pi$$
C
$${{100\pi } \over 3}$$
D
None of these
2
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

Let $$\alpha$$ be the solution of $${16^{{{\sin }^2}\theta }} + {16^{{{\cos }^2}\theta }} = 10$$ in $$\left( {0,{\pi \over 4}} \right)$$. If the shadow of a vertical pole is $${1 \over {\sqrt 3 }}$$ of its height, then the altitude of the sun is

A
$$\alpha$$
B
$${\alpha \over 2}$$
C
$$2\alpha$$
D
$${\alpha \over 3}$$
3
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

For each parabola y = x2 + px + q, meeting coordinate axes at 3-distinct points, if circles are drawn through these points, then the family of circles must pass through

A
(1, 0)
B
(0, 1)
C
(1, 1)
D
(p, q)
4
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

The number of ways of arranging letters of the word HAVANA so that V and N do not appear together is

A
40
B
60
C
80
D
100
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