Simplify the given expression.

$\frac{[120\times120\times120-100\times100\times100]}{[120\times120+120\times100+100\times100]}$

If (a + b + c) = 14, and (a³ + b³ + c³ - 3abc) = 98, find the value of (a² + b² + c²).

If (a + b + c) = 14, and (a³ + b³ + c³ - 3abc) = 98, find the value of (ab + bc + ca)

The sum of the cubes of two given natural numbers is 9728, while the sum of the two given numbers is 32 . What is the product of the two given numbers?