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GATE IN 2005
MCQ (Single Correct Answer)
+1
-0.3
The general solution of the differential equation $$\left( {{D^2} - 4D + 4} \right)y = 0$$ is of the form (given $$D = {d \over {dx}}$$ and $${C_1},{C_2}$$ are constants)
Questions Asked from Differential Equations (Marks 1)
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