CBSE 12th Physics (Term 1) Paper 2021-22 | Current Electricity Question 21 | Physics

CBSE 12th Physics (Term 1) Paper 2021-22

MCQ (Single Correct Answer)

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Two sources of equal emf are connected in series. This combination is, in turn connected to an external resistance R. The internal resistance of two sources are r₁ and r₂ (r₂ > r₁). If the potential difference across the source of internal resistance r₂ is zero, then R equals to -

$${{{r_1} + {r_2}} \over {{r_2} - {r_1}}}$$

$${r_2} - {r_1}$$

$${{{r_1}{r_2}} \over {{r_2} - {r_1}}}$$

$${{{r_1} + {r_2}} \over {{r_1}{r_2}}}$$

CBSE 12th Physics (Term 1) Paper 2021-22

MCQ (Single Correct Answer)

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The equivalent resistance between A and B of the network shown in figure is

CBSE 12th Physics (Term 1) Paper 2021-22 Physics - Current Electricity Question 19 English

CBSE 12th Physics (Term 1) Paper 2021-22 Physics - Current Electricity Question 19 English

3R $$\Omega$$

$$\left( {{3 \over 2}} \right)$$R $$\Omega$$

2R $$\Omega$$

$$\left( {{2 \over 3}} \right)$$R $$\Omega$$

CBSE 12th Physics (Term 1) Paper 2021-22

MCQ (Single Correct Answer)

+0.77

-0

Assertion (A) : Higher the range, lower is the resistance of an ammeter.

Reason (R) : To increase the range of an ammeter additional shunt is added in series to it.

Both (A) & (R) are true and (R) is correct explanation of (A).

Both (A) & (R) are true and (R) is not correct explanation of (A).

(A) is true but (R) is false.

(A) is false and (R) is also false.

CBSE 12th Physics (Term 1) Paper 2021-22

MCQ (Single Correct Answer)

+0.77

-0

Case Study :

An experiment was set up with the circuit diagram shown in figure. Given that R₁ = 10 $$\Omega$$, R₂ = R₃ = 5 $$\Omega$$, r = 0 $$\Omega$$ and E = 5 V

CBSE 12th Physics (Term 1) Paper 2021-22 Physics - Current Electricity Question 25 English Comprehension