1
JEE Main 2023 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

If the equation of the plane containing the line

$$x+2 y+3 z-4=0=2 x+y-z+5$$ and perpendicular to the plane

$\vec{r}=(\hat{i}-\hat{j})+\lambda(\hat{i}+\hat{j}+\hat{k})+\mu(\hat{i}-2 \hat{j}+3 \hat{k})$

is $a x+b y+c z=4$, then $$(a-b+c)$$ is equal to :

A
18
B
22
C
20
D
24
2
JEE Main 2023 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

Let $$P=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right], A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]$$ and $$Q=P A P^{T}$$. If $$P^{T} Q^{2007} P=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]$$, then $$2 a+b-3 c-4 d$$ equal to :

A
2004
B
2006
C
2007
D
2005
3
JEE Main 2023 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Change Language

If for $$z=\alpha+i \beta,|z+2|=z+4(1+i)$$, then $$\alpha+\beta$$ and $$\alpha \beta$$ are the roots of the equation :

A
$$x^{2}+2 x-3=0$$
B
$$x^{2}+3 x-4=0$$
C
$$x^{2}+x-12=0$$
D
$$x^{2}+7 x+12=0$$
4
JEE Main 2023 (Online) 8th April Morning Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language

Negation of $$(p \Rightarrow q) \Rightarrow(q \Rightarrow p)$$ is :

A
$$(\sim q) \wedge p$$
B
$$q \wedge(\sim p)$$
C
$$p \vee(\sim q)$$
D
$$(\sim p) \vee q$$
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