1
JEE Main 2021 (Online) 27th August Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
A differential equation representing the family of parabolas with axis parallel to y-axis and whose length of latus rectum is the distance of the point (2, $$-$$3) from the line 3x + 4y = 5, is given by :
A
$$10{{{d^2}y} \over {d{x^2}}} = 11$$
B
$$11{{{d^2}x} \over {d{y^2}}} = 10$$
C
$$10{{{d^2}x} \over {d{y^2}}} = 11$$
D
$$11{{{d^2}y} \over {d{x^2}}} = 10$$
2
JEE Main 2021 (Online) 27th August Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
If two tangents drawn from a point P to the
parabola y2 = 16(x $$-$$ 3) are at right angles, then the locus of point P is :
A
x + 3 = 0
B
x + 1 = 0
C
x + 2 = 0
D
x + 4 = 0
3
JEE Main 2021 (Online) 27th August Evening Shift
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The equation of the plane passing through the line of intersection of the planes $$\overrightarrow r .\left( {\widehat i + \widehat j + \widehat k} \right) = 1$$ and $$\overrightarrow r .\left( {2\widehat i + 3\widehat j - \widehat k} \right) + 4 = 0$$ and parallel to the x-axis is :
A
$$\overrightarrow r .\left( {\widehat j - 3\widehat k} \right) + 6 = 0$$
B
$$\overrightarrow r .\left( {\widehat i + 3\widehat k} \right) + 6 = 0$$
C
$$\overrightarrow r .\left( {\widehat i - 3\widehat k} \right) + 6 = 0$$
D
$$\overrightarrow r .\left( {\widehat j - 3\widehat k} \right) - 6 = 0$$
4
JEE Main 2021 (Online) 27th August Evening Shift
MCQ (Single Correct Answer)
+4
-1
Change Language
If the solution curve of the differential equation (2x $$-$$ 10y3)dy + ydx = 0, passes through the points (0, 1) and (2, $$\beta$$), then $$\beta$$ is a root of the equation :
A
y5 $$-$$ 2y $$-$$ 2 = 0
B
2y5 $$-$$ 2y $$-$$ 1 = 0
C
2y5 $$-$$ y2 $$-$$ 2 = 0
D
y5 $$-$$ y2 $$-$$ 1 = 0
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