1
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The perpendicular distance from the origin to the plane containing the two lines,

$${{x + 2} \over 3} = {{y - 2} \over 5} = {{z + 5} \over 7}$$ and

$${{x - 1} \over 1} = {{y - 4} \over 4} = {{z + 4} \over 7},$$ is :
A
$$6\sqrt {11} $$
B
$${{11} \over {\sqrt 6 }}$$
C
11
D
11$$\sqrt 6 $$
2
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
If the straight line, 2x – 3y + 17 = 0 is perpendicular to the line passing through the points (7, 17) and (15, $$\beta $$), then $$\beta $$ equals :
A
$${{35} \over 3}$$
B
$$-$$ 5
C
$$-$$ $${{35} \over 3}$$
D
5
3
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
For x > 1, if (2x)2y = 4e2x$$-$$2y,

then (1 + loge 2x)2 $${{dy} \over {dx}}$$ is equal to :
A
$${{x\,{{\log }_e}2x - {{\log }_e}2} \over x}$$
B
loge 2x
C
x loge 2x
D
$${{x\,{{\log }_e}2x + {{\log }_e}2} \over x}$$
4
JEE Main 2019 (Online) 12th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The area (in sq. units) of the region bounded by the parabola, y = x2 + 2 and the lines, y = x + 1, x = 0 and x = 3, is
A
$${{15} \over 4}$$
B
$${{15} \over 2}$$
C
$${{21} \over 2}$$
D
$${{17} \over 4}$$
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