1
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The two monomers for the synthesis of Nylon 6, 6 are
A
HOOC(CH2)6COOH, H2N(CH2)4NH2
B
HOOC(CH2)4COOH, H2N(CH2)6NH2
C
HOOC(CH2)4COOH, H2N(CH2)4NH2
D
HOOC(CH2)6COOH, H2N(CH2)6NH2
2
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The pair that does NOT require calcination is -
A
Fe2O3 and CaCO3⋅MgCO3
B
ZnCO3 and CaO
C
ZnO and Fe2O3⋅xH2O
D
ZnO and MgO
3
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The element that shows greater ability to form p$$\pi $$-p$$\pi $$ multiple bonds, is :
A
Si
B
Ge
C
C
D
Sn
4
JEE Main 2019 (Online) 12th January Evening Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The major product of the following reaction is :

JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 90 English
A
CH3CH2C$$ \equiv $$CH
B
CH3CH=C=CH2
C
JEE Main 2019 (Online) 12th January Evening Slot Chemistry - Hydrocarbons Question 90 English Option 3
D
CH3CH=CHCH2NH2
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