1
JEE Main 2019 (Online) 11th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The polymer obtained from the following reaction is :

JEE Main 2019 (Online) 11th January Morning Slot Chemistry - Polymers Question 60 English
A
JEE Main 2019 (Online) 11th January Morning Slot Chemistry - Polymers Question 60 English Option 1
B
JEE Main 2019 (Online) 11th January Morning Slot Chemistry - Polymers Question 60 English Option 2
C
JEE Main 2019 (Online) 11th January Morning Slot Chemistry - Polymers Question 60 English Option 3
D
JEE Main 2019 (Online) 11th January Morning Slot Chemistry - Polymers Question 60 English Option 4
2
JEE Main 2019 (Online) 11th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
Let $$f\left( x \right) = \left\{ {\matrix{ { - 1} & { - 2 \le x < 0} \cr {{x^2} - 1,} & {0 \le x \le 2} \cr } } \right.$$ and

$$g(x) = \left| {f\left( x \right)} \right| + f\left( {\left| x \right|} \right).$$

Then, in the interval (–2, 2), g is :
A
non continuous
B
differentiable at all points
C
not differentiable at two points
D
not differentiable at one point
3
JEE Main 2019 (Online) 11th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
Change Language
The value of r for which 20Cr 20C0 + 20Cr$$-$$1 20C1 + 20Cr$$-$$2 20C2 + . . . . .+ 20C0 20Cr  is maximum, is
A
20
B
15
C
10
D
11
4
JEE Main 2019 (Online) 11th January Morning Slot
MCQ (Single Correct Answer)
+4
-1
Change Language
The value of the integral $$\int\limits_{ - 2}^2 {{{{{\sin }^2}x} \over { \left[ {{x \over \pi }} \right] + {1 \over 2}}}} \,dx$$ (where [x] denotes the greatest integer less than or equal to x) is
A
0
B
4
C
4$$-$$ sin 4
D
sin 4
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