1
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The image of the line $${{x - 1} \over 3} = {{y - 3} \over 1} = {{z - 4} \over { - 5}}\,$$ in the plane $$2x-y+z+3=0$$ is the line :
A
$${{x - 3} \over 3} = {{y + 5} \over 1} = {{z - 2} \over { - 5}}$$
B
$${{x - 3} \over { - 3}} = {{y + 5} \over { - 1}} = {{z - 2} \over 5}\,$$
C
$${{x + 3} \over 3} = {{y - 5} \over 1} = {{z - 2} \over { - 5}}\,$$
D
$${{x + 3} \over { - 3}} = {{y - 5} \over { - 1}} = {{z + 2} \over 5}$$
2
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
The angle between the lines whose direction cosines satisfy the equations $$l+m+n=0$$ and $${l^2} = {m^2} + {n^2}$$ is :
A
$${\pi \over 6}$$
B
$${\pi \over 2}$$
C
$${\pi \over 3}$$
D
$${\pi \over 4}$$
3
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
If $$\left[ {\overrightarrow a \times \overrightarrow b \,\,\,\,\overrightarrow b \times \overrightarrow c \,\,\,\,\overrightarrow c \times \overrightarrow a } \right] = \lambda {\left[ {\overrightarrow a\,\,\,\,\,\,\,\, \overrightarrow b \,\,\,\,\,\,\,\,\overrightarrow c } \right]^2}$$ then $$\lambda $$ is equal to :
A
$$0$$
B
$$1$$
C
$$2$$
D
$$3$$
4
JEE Main 2014 (Offline)
MCQ (Single Correct Answer)
+4
-1
$$\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}$$ is equal to :
A
$$ - \pi $$
B
$$ \pi $$
C
$${\pi \over 2}$$
D
1
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