1
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
The two circles x2 + y2 = ax, and x2 + y2 = c2 (c > 0) touch each other if :
A
| a | = c
B
a = 2c
C
| a | = 2c
D
2 | a | = c
2
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
Equation of the ellipse whose axes of coordinates and which passes through the point $$(-3,1)$$ and has eccentricity $$\sqrt {{2 \over 5}} $$ is :
A
$$5{x^2} + 3{y^2} - 48 = 0$$
B
$$3{x^2} + 5{y^2} - 15 = 0$$
C
$$5{x^2} + 3{y^2} - 32 = 0$$
D
$$3{x^2} + 5{y^2} - 32 = 0$$
3
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
$${{{d^2}x} \over {d{y^2}}}$$ equals:
A
$$ - {\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{ - 1}}{\left( {{{dy} \over {dx}}} \right)^{ - 3}}$$
B
$${\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{}}{\left( {{{dy} \over {dx}}} \right)^{ - 2}}$$
C
$$ - \left( {{{{d^2}y} \over {d{x^2}}}} \right){\left( {{{dy} \over {dx}}} \right)^{ - 3}}$$
D
$${\left( {{{{d^2}y} \over {d{x^2}}}} \right)^{ - 1}}$$
4
AIEEE 2011
MCQ (Single Correct Answer)
+4
-1
For $$x \in \left( {0,{{5\pi } \over 2}} \right),$$ define $$f\left( x \right) = \int\limits_0^x {\sqrt t \sin t\,dt.} $$ Then $$f$$ has
A
local minimum at $$\pi $$ and $$2\pi $$
B
local minimum at $$\pi $$ and local maximum at $$2\pi $$
C
local maximum at $$\pi $$ and local minimum at $$2\pi $$
D
local maximum at $$\pi $$ and $$2\pi $$
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