1
JEE Advanced 2021 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Precipitate X is
A
Fe4[Fe(CN)6]3
B
Fe[Fe(CN)6]
C
K2Fe[Fe(CN)6]
D
KFe[Fe(CN)6]
2
JEE Advanced 2021 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of
A
[Fe(NO)2](SO4)2]2$$-$$
B
[Fe(NO)2](H2O)4]3+
C
[Fe(NO)4](SO4)2]
D
[Fe(NO)(H2O)5]2+
3
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

JEE Advanced 2014 Paper 2 Offline Chemistry - Salt Analysis Question 15 English Comprehension

M1, Q and R, respectively, are
A
Zn2+, KCN and HCl
B
Ni2+, HCl and KCN
C
Cd2+, KCN and HCl
D
Co2+, HCl and KCN
4
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:

SCHEME:

JEE Advanced 2014 Paper 2 Offline Chemistry - Salt Analysis Question 16 English Comprehension

Reagent S is

A
K4[Fe(CN)6]
B
Na2HPO4
C
K2CrO4
D
KOH
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